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855211029117 = 3285070343039
BaseRepresentation
bin11000111000111101000…
…11001011001001111101
310000202110010102121200220
430130132203023021331
5103002433010412432
61452513432211553
7115533632543334
oct14343643131175
93022403377626
10855211029117
112aa769370085
121198b4539bb9
13628524c4383
142d56cbaad1b
15173a53c572c
hexc71e8cb27d

855211029117 has 4 divisors (see below), whose sum is σ = 1140281372160. Its totient is φ = 570140686076.

The previous prime is 855211029077. The next prime is 855211029131. The reversal of 855211029117 is 711920112558.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 855211029117 - 210 = 855211028093 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (855211029217) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 142535171517 + ... + 142535171522.

It is an arithmetic number, because the mean of its divisors is an integer number (285070343040).

Almost surely, 2855211029117 is an apocalyptic number.

It is an amenable number.

855211029117 is a deficient number, since it is larger than the sum of its proper divisors (285070343043).

855211029117 is a wasteful number, since it uses less digits than its factorization.

855211029117 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 285070343042.

The product of its (nonzero) digits is 50400, while the sum is 42.

The spelling of 855211029117 in words is "eight hundred fifty-five billion, two hundred eleven million, twenty-nine thousand, one hundred seventeen".

Divisors: 1 3 285070343039 855211029117