Base | Representation |
---|---|
bin | 100111110101101111… |
… | …0101111011101100111 |
3 | 22011211110222112102220 |
4 | 1033223132233131213 |
5 | 2400204100124421 |
6 | 103145314203423 |
7 | 6116064131121 |
oct | 1175336573547 |
9 | 264743875386 |
10 | 85555083111 |
11 | 33313683263 |
12 | 146b8283573 |
13 | 80b5c93744 |
14 | 41d8850211 |
15 | 235b01e3c6 |
hex | 13eb7af767 |
85555083111 has 4 divisors (see below), whose sum is σ = 114073444152. Its totient is φ = 57036722072.
The previous prime is 85555083079. The next prime is 85555083127. The reversal of 85555083111 is 11138055558.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 85555083111 - 25 = 85555083079 is a prime.
It is a super-2 number, since 2×855550831112 (a number of 23 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (85555083181) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 14259180516 + ... + 14259180521.
It is an arithmetic number, because the mean of its divisors is an integer number (28518361038).
Almost surely, 285555083111 is an apocalyptic number.
85555083111 is a deficient number, since it is larger than the sum of its proper divisors (28518361041).
85555083111 is a wasteful number, since it uses less digits than its factorization.
85555083111 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 28518361040.
The product of its (nonzero) digits is 120000, while the sum is 42.
The spelling of 85555083111 in words is "eighty-five billion, five hundred fifty-five million, eighty-three thousand, one hundred eleven".
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