Base | Representation |
---|---|
bin | 100111111001011110… |
… | …0011101101000111111 |
3 | 22012011012121222012220 |
4 | 1033302330131220333 |
5 | 2400433130034233 |
6 | 103205550300423 |
7 | 6122144442366 |
oct | 1176274355077 |
9 | 265135558186 |
10 | 85680314943 |
11 | 33378338843 |
12 | 147321b7713 |
13 | 8105bccb12 |
14 | 420b32c7dd |
15 | 2367009eb3 |
hex | 13f2f1da3f |
85680314943 has 8 divisors (see below), whose sum is σ = 114241981056. Its totient is φ = 57119429400.
The previous prime is 85680314927. The next prime is 85680314969. The reversal of 85680314943 is 34941308658.
It is a Cunningham number, because it is equal to 2927122-1.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 85680314943 - 24 = 85680314927 is a prime.
It is a super-2 number, since 2×856803149432 (a number of 23 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (85680314903) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 146358 + ... + 439068.
It is an arithmetic number, because the mean of its divisors is an integer number (14280247632).
Almost surely, 285680314943 is an apocalyptic number.
85680314943 is a deficient number, since it is larger than the sum of its proper divisors (28561666113).
85680314943 is a wasteful number, since it uses less digits than its factorization.
85680314943 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 390285.
The product of its (nonzero) digits is 2488320, while the sum is 51.
The spelling of 85680314943 in words is "eighty-five billion, six hundred eighty million, three hundred fourteen thousand, nine hundred forty-three".
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