Base | Representation |
---|---|
bin | 11000111100010111001… |
… | …10001110110101001011 |
3 | 10000221011121222202121221 |
4 | 30132023212032311023 |
5 | 103020204340002042 |
6 | 1453415145142511 |
7 | 115630156311211 |
oct | 14361346166513 |
9 | 3027147882557 |
10 | 857040547147 |
11 | 300518056054 |
12 | 11a12518aa37 |
13 | 62a8454ac15 |
14 | 2d6a3b68cb1 |
15 | 17460d0ed67 |
hex | c78b98ed4b |
857040547147 has 4 divisors (see below), whose sum is σ = 880203805216. Its totient is φ = 833877289080.
The previous prime is 857040547087. The next prime is 857040547183. The reversal of 857040547147 is 741745040758.
It is a happy number.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 857040547147 - 211 = 857040545099 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 857040547094 and 857040547103.
It is not an unprimeable number, because it can be changed into a prime (857040517147) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 11581628979 + ... + 11581629052.
It is an arithmetic number, because the mean of its divisors is an integer number (220050951304).
Almost surely, 2857040547147 is an apocalyptic number.
857040547147 is a deficient number, since it is larger than the sum of its proper divisors (23163258069).
857040547147 is a wasteful number, since it uses less digits than its factorization.
857040547147 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 23163258068.
The product of its (nonzero) digits is 4390400, while the sum is 52.
The spelling of 857040547147 in words is "eight hundred fifty-seven billion, forty million, five hundred forty-seven thousand, one hundred forty-seven".
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