Base | Representation |
---|---|
bin | 10011101010100110101001… |
… | …100110110010101101101011 |
3 | 102100020102100202112022010101 |
4 | 103222212221212302231223 |
5 | 42314030223100131001 |
6 | 503541122314130231 |
7 | 24134511513352441 |
oct | 2352465146625553 |
9 | 370212322468111 |
10 | 86490601958251 |
11 | 25616505000137 |
12 | 984a55b720977 |
13 | 393504b28561a |
14 | 175024b77ab91 |
15 | 9eec443eea01 |
hex | 4ea9a99b2b6b |
86490601958251 has 4 divisors (see below), whose sum is σ = 86492108479392. Its totient is φ = 86489095437112.
The previous prime is 86490601958203. The next prime is 86490601958351. The reversal of 86490601958251 is 15285910609468.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-86490601958251 is a prime.
It is a super-2 number, since 2×864906019582512 (a number of 29 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (86490601958351) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 753174451 + ... + 753289276.
It is an arithmetic number, because the mean of its divisors is an integer number (21623027119848).
Almost surely, 286490601958251 is an apocalyptic number.
86490601958251 is a deficient number, since it is larger than the sum of its proper divisors (1506521141).
86490601958251 is a wasteful number, since it uses less digits than its factorization.
86490601958251 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1506521140.
The product of its (nonzero) digits is 37324800, while the sum is 64.
The spelling of 86490601958251 in words is "eighty-six trillion, four hundred ninety billion, six hundred one million, nine hundred fifty-eight thousand, two hundred fifty-one".
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