Base | Representation |
---|---|
bin | 11001010100110000001… |
… | …10000101010111111111 |
3 | 10002011222012202021012111 |
4 | 30222120012011113333 |
5 | 103224014043004003 |
6 | 1503422355314451 |
7 | 116602521350410 |
oct | 14523006052777 |
9 | 3064865667174 |
10 | 870135125503 |
11 | 306027659636 |
12 | 12077a5aba27 |
13 | 640903b5737 |
14 | 30186cb3807 |
15 | 1797a6e4e6d |
hex | ca981855ff |
870135125503 has 4 divisors (see below), whose sum is σ = 994440143440. Its totient is φ = 745830107568.
The previous prime is 870135125479. The next prime is 870135125537. The reversal of 870135125503 is 305521531078.
It is a semiprime because it is the product of two primes.
It is a de Polignac number, because none of the positive numbers 2k-870135125503 is a prime.
It is a super-2 number, since 2×8701351255032 (a number of 25 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (870135125543) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 62152508958 + ... + 62152508971.
It is an arithmetic number, because the mean of its divisors is an integer number (248610035860).
Almost surely, 2870135125503 is an apocalyptic number.
870135125503 is a deficient number, since it is larger than the sum of its proper divisors (124305017937).
870135125503 is a wasteful number, since it uses less digits than its factorization.
870135125503 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 124305017936.
The product of its (nonzero) digits is 126000, while the sum is 40.
The spelling of 870135125503 in words is "eight hundred seventy billion, one hundred thirty-five million, one hundred twenty-five thousand, five hundred three".
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