Base | Representation |
---|---|
bin | 101001001010000011… |
… | …1101110111110111101 |
3 | 22110010122211210101222 |
4 | 1102110013232332331 |
5 | 2422002401320331 |
6 | 104334144243125 |
7 | 6246151005245 |
oct | 1222407567675 |
9 | 273118753358 |
10 | 88384401341 |
11 | 34535765995 |
12 | 151679104a5 |
13 | 84471b7542 |
14 | 43c6506b25 |
15 | 24745eab7b |
hex | 14941eefbd |
88384401341 has 4 divisors (see below), whose sum is σ = 88480576800. Its totient is φ = 88288225884.
The previous prime is 88384401317. The next prime is 88384401353. The reversal of 88384401341 is 14310448388.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 88384401341 - 222 = 88380207037 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 88384401292 and 88384401301.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (88384401641) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 48086351 + ... + 48088188.
It is an arithmetic number, because the mean of its divisors is an integer number (22120144200).
Almost surely, 288384401341 is an apocalyptic number.
It is an amenable number.
88384401341 is a deficient number, since it is larger than the sum of its proper divisors (96175459).
88384401341 is an equidigital number, since it uses as much as digits as its factorization.
88384401341 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 96175458.
The product of its (nonzero) digits is 294912, while the sum is 44.
The spelling of 88384401341 in words is "eighty-eight billion, three hundred eighty-four million, four hundred one thousand, three hundred forty-one".
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