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894540483141 = 3298180161047
BaseRepresentation
bin11010000010001101100…
…01001000101001000101
310011111222001201220001020
431001012301020221011
5104124004330430031
61522540215021353
7121425355435524
oct15010661105105
93144861656036
10894540483141
11315410866a98
1212544b96a859
136647c67ab66
14314202aa4bb
15184080a7096
hexd046c48a45

894540483141 has 4 divisors (see below), whose sum is σ = 1192720644192. Its totient is φ = 596360322092.

The previous prime is 894540483091. The next prime is 894540483143. The reversal of 894540483141 is 141384045498.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 894540483141 - 222 = 894536288837 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (894540483143) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 149090080521 + ... + 149090080526.

It is an arithmetic number, because the mean of its divisors is an integer number (298180161048).

Almost surely, 2894540483141 is an apocalyptic number.

It is an amenable number.

894540483141 is a deficient number, since it is larger than the sum of its proper divisors (298180161051).

894540483141 is a wasteful number, since it uses less digits than its factorization.

894540483141 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 298180161050.

The product of its (nonzero) digits is 2211840, while the sum is 51.

The spelling of 894540483141 in words is "eight hundred ninety-four billion, five hundred forty million, four hundred eighty-three thousand, one hundred forty-one".

Divisors: 1 3 298180161047 894540483141