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9136410010055 = 51827282002011
BaseRepresentation
bin1000010011110011110001…
…1110010010000111000111
31012100102200010022022200222
42010330330132102013013
52144142331430310210
631233113034254555
71632040520503466
oct204747436220707
935312603268628
109136410010055
112a028032a0729
12103684528745b
13513737a67b83
142382c160c9dd
1510c9d4167655
hex84f3c7921c7

9136410010055 has 4 divisors (see below), whose sum is σ = 10963692012072. Its totient is φ = 7309128008040.

The previous prime is 9136410010043. The next prime is 9136410010111. The reversal of 9136410010055 is 5500100146319.

9136410010055 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It is not a de Polignac number, because 9136410010055 - 28 = 9136410009799 is a prime.

It is a super-2 number, since 2×91364100100552 (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 9136410009997 and 9136410010024.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 913641001001 + ... + 913641001010.

It is an arithmetic number, because the mean of its divisors is an integer number (2740923003018).

Almost surely, 29136410010055 is an apocalyptic number.

9136410010055 is a deficient number, since it is larger than the sum of its proper divisors (1827282002017).

9136410010055 is a wasteful number, since it uses less digits than its factorization.

9136410010055 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1827282002016.

The product of its (nonzero) digits is 16200, while the sum is 35.

The spelling of 9136410010055 in words is "nine trillion, one hundred thirty-six billion, four hundred ten million, ten thousand, fifty-five".

Divisors: 1 5 1827282002011 9136410010055