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93125327887 = 293211218203
BaseRepresentation
bin101011010111010110…
…0111011110000001111
322220101001201211000001
41112232230323300033
53011210040443022
6110440422545131
76504506140444
oct1265654736017
9286331654001
1093125327887
11365489021a9
121606b5981a7
138a21477817
1447160099cb
152650929b27
hex15aeb3bc0f

93125327887 has 4 divisors (see below), whose sum is σ = 96336546120. Its totient is φ = 89914109656.

The previous prime is 93125327881. The next prime is 93125327899. The reversal of 93125327887 is 78872352139.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-93125327887 is a prime.

It is a super-2 number, since 2×931253278872 (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (93125327881) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1605609073 + ... + 1605609130.

It is an arithmetic number, because the mean of its divisors is an integer number (24084136530).

Almost surely, 293125327887 is an apocalyptic number.

93125327887 is a deficient number, since it is larger than the sum of its proper divisors (3211218233).

93125327887 is a wasteful number, since it uses less digits than its factorization.

93125327887 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3211218232.

The product of its digits is 5080320, while the sum is 55.

The spelling of 93125327887 in words is "ninety-three billion, one hundred twenty-five million, three hundred twenty-seven thousand, eight hundred eighty-seven".

Divisors: 1 29 3211218203 93125327887