94331211213307 has 4 divisors (see below), whose sum is σ = 94331236617280. Its totient is φ = 94331185809336.

The previous prime is 94331211213271. The next prime is 94331211213377. The reversal of 94331211213307 is 70331211213349.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 94331211213307 - 2⁷ = 94331211213179 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 94331211213307.

It is not an unprimeable number, because it can be changed into a prime (94331211213377) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5927883 + ... + 14960020.

It is an arithmetic number, because the mean of its divisors is an integer number (23582809154320).

Almost surely, 2^{94331211213307} is an apocalyptic number.

94331211213307 is a deficient number, since it is larger than the sum of its proper divisors (25403973).

94331211213307 is a wasteful number, since it uses less digits than its factorization.

94331211213307 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 25403972.

The product of its (nonzero) digits is 81648, while the sum is 40.

The spelling of 94331211213307 in words is "ninety-four trillion, three hundred thirty-one billion, two hundred eleven million, two hundred thirteen thousand, three hundred seven".