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94804460003483 = 106507389012171
BaseRepresentation
bin10101100011100101100010…
…001010010110000010011011
3110102200012212211012100222022
4111203211202022112002123
544411234013230102413
6533344322341245055
725653252616631516
oct2543454212260233
9412605784170868
1094804460003483
112823138914110a
12a7718a5a0378b
1340b9039a74239
14195a7bb841d7d
15ae6135466608
hex56396229609b

94804460003483 has 4 divisors (see below), whose sum is σ = 94804550080728. Its totient is φ = 94804369926240.

The previous prime is 94804460003399. The next prime is 94804460003531. The reversal of 94804460003483 is 38430006440849.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 94804460003483 - 216 = 94804459937947 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (94804460003083) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 43441013 + ... + 45571158.

It is an arithmetic number, because the mean of its divisors is an integer number (23701137520182).

Almost surely, 294804460003483 is an apocalyptic number.

94804460003483 is a deficient number, since it is larger than the sum of its proper divisors (90077245).

94804460003483 is a wasteful number, since it uses less digits than its factorization.

94804460003483 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 90077244.

The product of its (nonzero) digits is 7962624, while the sum is 53.

The spelling of 94804460003483 in words is "ninety-four trillion, eight hundred four billion, four hundred sixty million, three thousand, four hundred eighty-three".

Divisors: 1 1065073 89012171 94804460003483