Base | Representation |
---|---|
bin | 101101000110010001… |
… | …1100100011001110111 |
3 | 100020222110111102111201 |
4 | 1122030203210121313 |
5 | 3041320414234103 |
6 | 112254024113331 |
7 | 6665653305211 |
oct | 1321443443167 |
9 | 306873442451 |
10 | 96847414903 |
11 | 38088928278 |
12 | 1692a005847 |
13 | 9195632785 |
14 | 498a4995b1 |
15 | 27bc5a551d |
hex | 168c8e4677 |
96847414903 has 4 divisors (see below), whose sum is σ = 102544321680. Its totient is φ = 91150508128.
The previous prime is 96847414877. The next prime is 96847414981. The reversal of 96847414903 is 30941474869.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 96847414903 - 217 = 96847283831 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (96847412903) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2848453363 + ... + 2848453396.
It is an arithmetic number, because the mean of its divisors is an integer number (25636080420).
Almost surely, 296847414903 is an apocalyptic number.
96847414903 is a deficient number, since it is larger than the sum of its proper divisors (5696906777).
96847414903 is a wasteful number, since it uses less digits than its factorization.
96847414903 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 5696906776.
The product of its (nonzero) digits is 5225472, while the sum is 55.
The spelling of 96847414903 in words is "ninety-six billion, eight hundred forty-seven million, four hundred fourteen thousand, nine hundred three".
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