Base | Representation |
---|---|
bin | 10110001010111101001000… |
… | …011000110101011001110001 |
3 | 110210020211222120220222111200 |
4 | 112022331020120311121301 |
5 | 100240100141342201313 |
6 | 543215224312001413 |
7 | 26352566104614240 |
oct | 2612751030653161 |
9 | 423224876828450 |
10 | 97509856990833 |
11 | 29084775216011 |
12 | ab2a091990269 |
13 | 42541a892c381 |
14 | 1a117062b6957 |
15 | b416c621db73 |
hex | 58af48635671 |
97509856990833 has 24 divisors (see below), whose sum is σ = 160969360656000. Its totient is φ = 55719673257024.
The previous prime is 97509856990801. The next prime is 97509856990853. The reversal of 97509856990833 is 33809965890579.
It is not a de Polignac number, because 97509856990833 - 25 = 97509856990801 is a prime.
It is not an unprimeable number, because it can be changed into a prime (97509856990853) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 11554893 + ... + 18125541.
It is an arithmetic number, because the mean of its divisors is an integer number (6707056694000).
Almost surely, 297509856990833 is an apocalyptic number.
It is an amenable number.
97509856990833 is a deficient number, since it is larger than the sum of its proper divisors (63459503665167).
97509856990833 is a wasteful number, since it uses less digits than its factorization.
97509856990833 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 6806221 (or 6806218 counting only the distinct ones).
The product of its (nonzero) digits is 3968092800, while the sum is 81.
The spelling of 97509856990833 in words is "ninety-seven trillion, five hundred nine billion, eight hundred fifty-six million, nine hundred ninety thousand, eight hundred thirty-three".
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