Base | Representation |
---|---|
bin | 101101100110101010… |
… | …1011001010011000001 |
3 | 100100210012111202200022 |
4 | 1123031111121103001 |
5 | 3101032124442213 |
6 | 112553530103225 |
7 | 10034621056502 |
oct | 1331525312301 |
9 | 310705452608 |
10 | 97934218433 |
11 | 38596349907 |
12 | 16b91b7ab15 |
13 | 930984299c |
14 | 4a50960ba9 |
15 | 2832bd1308 |
hex | 16cd5594c1 |
97934218433 has 8 divisors (see below), whose sum is σ = 98607136320. Its totient is φ = 97261621200.
The previous prime is 97934218423. The next prime is 97934218441. The reversal of 97934218433 is 33481243979.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 97934218433 - 220 = 97933169857 is a prime.
It is a super-2 number, since 2×979342184332 (a number of 23 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (97934218423) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 549698 + ... + 705716.
It is an arithmetic number, because the mean of its divisors is an integer number (12325892040).
Almost surely, 297934218433 is an apocalyptic number.
It is an amenable number.
97934218433 is a deficient number, since it is larger than the sum of its proper divisors (672917887).
97934218433 is a wasteful number, since it uses less digits than its factorization.
97934218433 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 160327.
The product of its digits is 3919104, while the sum is 53.
The spelling of 97934218433 in words is "ninety-seven billion, nine hundred thirty-four million, two hundred eighteen thousand, four hundred thirty-three".
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