Base | Representation |
---|---|
bin | 1000111010101010110011… |
… | …0010100110001000010011 |
3 | 1021201020212121120211220101 |
4 | 2032222230302212020103 |
5 | 2241112110131022003 |
6 | 32503522455353231 |
7 | 2031213420451540 |
oct | 216525462461023 |
9 | 37636777524811 |
10 | 9804014314003 |
11 | 313a94a5433a8 |
12 | 1124100682817 |
13 | 56168c7000a0 |
14 | 25c734249bc7 |
15 | 12005912011d |
hex | 8eaacca6213 |
9804014314003 has 16 divisors (see below), whose sum is σ = 12294148579776. Its totient is φ = 7610663399040.
The previous prime is 9804014313943. The next prime is 9804014314019. The reversal of 9804014314003 is 3004134104089.
It is not a de Polignac number, because 9804014314003 - 237 = 9666575360531 is a prime.
It is a super-2 number, since 2×98040143140032 (a number of 27 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (9804014314033) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1016376508 + ... + 1016386153.
It is an arithmetic number, because the mean of its divisors is an integer number (768384286236).
Almost surely, 29804014314003 is an apocalyptic number.
9804014314003 is a deficient number, since it is larger than the sum of its proper divisors (2490134265773).
9804014314003 is a wasteful number, since it uses less digits than its factorization.
9804014314003 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2032762734.
The product of its (nonzero) digits is 41472, while the sum is 37.
The spelling of 9804014314003 in words is "nine trillion, eight hundred four billion, fourteen million, three hundred fourteen thousand, three".
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