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98116264433 = 118919660403
BaseRepresentation
bin101101101100000101…
…1110110000111110001
3100101020220001122211202
41123120023312013301
53101420230430213
6113023552020545
710042261326035
oct1333013660761
9311226048752
1098116264433
113867a089750
1217022b31755
139338481c05
144a6abcc1c5
152843b90b58
hex16d82f61f1

98116264433 has 4 divisors (see below), whose sum is σ = 107035924848. Its totient is φ = 89196604020.

The previous prime is 98116264409. The next prime is 98116264451. The reversal of 98116264433 is 33446261189.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 33446261189 = 113040569199.

It is a cyclic number.

It is not a de Polignac number, because 98116264433 - 212 = 98116260337 is a prime.

It is a super-2 number, since 2×981162644332 (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is a Curzon number.

It is not an unprimeable number, because it can be changed into a prime (98116264333) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4459830191 + ... + 4459830212.

It is an arithmetic number, because the mean of its divisors is an integer number (26758981212).

Almost surely, 298116264433 is an apocalyptic number.

It is an amenable number.

98116264433 is a deficient number, since it is larger than the sum of its proper divisors (8919660415).

98116264433 is a wasteful number, since it uses less digits than its factorization.

98116264433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 8919660414.

The product of its digits is 746496, while the sum is 47.

The spelling of 98116264433 in words is "ninety-eight billion, one hundred sixteen million, two hundred sixty-four thousand, four hundred thirty-three".

Divisors: 1 11 8919660403 98116264433