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98713126453 = 217274543339
BaseRepresentation
bin101101111101111000…
…0101100011000110101
3100102210111011101121111
41123323300230120311
53104131030021303
6113203112515021
710063126505404
oct1337360543065
9312714141544
1098713126453
1138955a93a47
121716a9aba71
13940201c3c6
144ac619963b
15287b28db6d
hex16fbc2c635

98713126453 has 4 divisors (see below), whose sum is σ = 98717691520. Its totient is φ = 98708561388.

The previous prime is 98713126451. The next prime is 98713126481. The reversal of 98713126453 is 35462131789.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 98713126453 - 21 = 98713126451 is a prime.

It is a super-2 number, since 2×987131264532 (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 98713126397 and 98713126406.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (98713126451) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2249943 + ... + 2293396.

It is an arithmetic number, because the mean of its divisors is an integer number (24679422880).

Almost surely, 298713126453 is an apocalyptic number.

It is an amenable number.

98713126453 is a deficient number, since it is larger than the sum of its proper divisors (4565067).

98713126453 is a wasteful number, since it uses less digits than its factorization.

98713126453 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4565066.

The product of its digits is 1088640, while the sum is 49.

The spelling of 98713126453 in words is "ninety-eight billion, seven hundred thirteen million, one hundred twenty-six thousand, four hundred fifty-three".

Divisors: 1 21727 4543339 98713126453