99148609963 has 4 divisors (see below), whose sum is σ = 106775426128. Its totient is φ = 91521793800.

The previous prime is 99148609943. The next prime is 99148609981. The reversal of 99148609963 is 36990684199.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 99148609963 - 2²¹ = 99146512811 is a prime.

It is a super-2 number, since 2×99148609963² (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 99148609895 and 99148609904.

It is not an unprimeable number, because it can be changed into a prime (99148609913) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3813408063 + ... + 3813408088.

It is an arithmetic number, because the mean of its divisors is an integer number (26693856532).

Almost surely, 2^99148609963 is an apocalyptic number.

99148609963 is a deficient number, since it is larger than the sum of its proper divisors (7626816165).

99148609963 is a wasteful number, since it uses less digits than its factorization.

99148609963 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 7626816164.

The product of its (nonzero) digits is 22674816, while the sum is 64.

The spelling of 99148609963 in words is "ninety-nine billion, one hundred forty-eight million, six hundred nine thousand, nine hundred sixty-three".