9917196381263 has 4 divisors (see below), whose sum is σ = 10439154085560. Its totient is φ = 9395238676968.

The previous prime is 9917196381223. The next prime is 9917196381283. The reversal of 9917196381263 is 3621836917199.

9917196381263 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 9917196381263 - 2¹⁰ = 9917196380239 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 9917196381263.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (9917196381223) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 260978852120 + ... + 260978852157.

It is an arithmetic number, because the mean of its divisors is an integer number (2609788521390).

Almost surely, 2^{9917196381263} is an apocalyptic number.

9917196381263 is a deficient number, since it is larger than the sum of its proper divisors (521957704297).

9917196381263 is a wasteful number, since it uses less digits than its factorization.

9917196381263 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 521957704296.

The product of its digits is 26453952, while the sum is 65.

The spelling of 9917196381263 in words is "nine trillion, nine hundred seventeen billion, one hundred ninety-six million, three hundred eighty-one thousand, two hundred sixty-three".