Base | Representation |
---|---|
bin | 101110001011100100… |
… | …0101110000100110011 |
3 | 100110222111101101201022 |
4 | 1130113020232010303 |
5 | 3111101114102101 |
6 | 113320440530055 |
7 | 10110404400440 |
oct | 1342710560463 |
9 | 313874341638 |
10 | 99172409651 |
11 | 39071270237 |
12 | 1727878092b |
13 | 9476219603 |
14 | 4b2b1929c7 |
15 | 28a6762a1b |
hex | 171722e133 |
99172409651 has 4 divisors (see below), whose sum is σ = 113339896752. Its totient is φ = 85004922552.
The previous prime is 99172409629. The next prime is 99172409653. The reversal of 99172409651 is 15690427199.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 99172409651 - 210 = 99172408627 is a prime.
It is a super-3 number, since 3×991724096513 (a number of 34 digits) contains 333 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 99172409593 and 99172409602.
It is not an unprimeable number, because it can be changed into a prime (99172409653) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 7083743540 + ... + 7083743553.
It is an arithmetic number, because the mean of its divisors is an integer number (28334974188).
Almost surely, 299172409651 is an apocalyptic number.
99172409651 is a deficient number, since it is larger than the sum of its proper divisors (14167487101).
99172409651 is a wasteful number, since it uses less digits than its factorization.
99172409651 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 14167487100.
The product of its (nonzero) digits is 1224720, while the sum is 53.
The spelling of 99172409651 in words is "ninety-nine billion, one hundred seventy-two million, four hundred nine thousand, six hundred fifty-one".
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