Base | Representation |
---|---|
bin | 101110001101111101… |
… | …1111101010000110111 |
3 | 100111012002221021101211 |
4 | 1130123323331100313 |
5 | 3111232223400241 |
6 | 113332435102251 |
7 | 10112403104242 |
oct | 1343373752067 |
9 | 314162837354 |
10 | 99252950071 |
11 | 39102780470 |
12 | 1729b741987 |
13 | 9489b08972 |
14 | 4b37b5a259 |
15 | 28ad871781 |
hex | 171befd437 |
99252950071 has 8 divisors (see below), whose sum is σ = 108310150800. Its totient is φ = 90201450240.
The previous prime is 99252950053. The next prime is 99252950087. The reversal of 99252950071 is 17005925299.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 99252950071 - 229 = 98716079159 is a prime.
It is a super-2 number, since 2×992529500712 (a number of 23 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 99252949997 and 99252950024.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (99252950011) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1388776 + ... + 1458493.
It is an arithmetic number, because the mean of its divisors is an integer number (13538768850).
Almost surely, 299252950071 is an apocalyptic number.
99252950071 is a deficient number, since it is larger than the sum of its proper divisors (9057200729).
99252950071 is a wasteful number, since it uses less digits than its factorization.
99252950071 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2850449.
The product of its (nonzero) digits is 510300, while the sum is 49.
The spelling of 99252950071 in words is "ninety-nine billion, two hundred fifty-two million, nine hundred fifty thousand, seventy-one".
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