9940413225103 has 4 divisors (see below), whose sum is σ = 9959942524680. Its totient is φ = 9920883925528.

The previous prime is 9940413225049. The next prime is 9940413225139. The reversal of 9940413225103 is 3015223140499.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 9940413225103 - 2³³ = 9931823290511 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 9940413225103.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (9940413225203) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 9764649025 + ... + 9764650042.

It is an arithmetic number, because the mean of its divisors is an integer number (2489985631170).

Almost surely, 2^{9940413225103} is an apocalyptic number.

9940413225103 is a deficient number, since it is larger than the sum of its proper divisors (19529299577).

9940413225103 is a wasteful number, since it uses less digits than its factorization.

9940413225103 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 19529299576.

The product of its (nonzero) digits is 233280, while the sum is 43.

The spelling of 9940413225103 in words is "nine trillion, nine hundred forty billion, four hundred thirteen million, two hundred twenty-five thousand, one hundred three".