9940990953 has 16 divisors (see below), whose sum is σ = 13393086336. Its totient is φ = 6558182400.

The previous prime is 9940990949. The next prime is 9940990973. The reversal of 9940990953 is 3590990499.

It is not a de Polignac number, because 9940990953 - 2² = 9940990949 is a prime.

It is a super-2 number, since 2×9940990953² (a number of 21 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 9940990893 and 9940990902.

It is not an unprimeable number, because it can be changed into a prime (9940990973) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 632476 + ... + 648002.

It is an arithmetic number, because the mean of its divisors is an integer number (837067896).

Almost surely, 2^9940990953 is an apocalyptic number.

It is an amenable number.

9940990953 is a deficient number, since it is larger than the sum of its proper divisors (3452095383).

9940990953 is a wasteful number, since it uses less digits than its factorization.

9940990953 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 17744.

The product of its (nonzero) digits is 3542940, while the sum is 57.

The square root of 9940990953 is about 99704.5182175813. The cubic root of 9940990953 is about 2150.1886225716.

The spelling of 9940990953 in words is "nine billion, nine hundred forty million, nine hundred ninety thousand, nine hundred fifty-three".