9991354029253 has 4 divisors (see below), whose sum is σ = 9991361325420. Its totient is φ = 9991346733088.

The previous prime is 9991354029233. The next prime is 9991354029289. The reversal of 9991354029253 is 3529204531999.

It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length.

It can be written as a sum of positive squares in 2 ways, for example, as 8681844571009 + 1309509458244 = 2946497^2 + 1144338^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-9991354029253 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 9991354029191 and 9991354029200.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (9991354029203) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 907918 + ... + 4561471.

It is an arithmetic number, because the mean of its divisors is an integer number (2497840331355).

Almost surely, 2^{9991354029253} is an apocalyptic number.

It is an amenable number.

9991354029253 is a deficient number, since it is larger than the sum of its proper divisors (7296167).

9991354029253 is a wasteful number, since it uses less digits than its factorization.

9991354029253 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 7296166.

The product of its (nonzero) digits is 23619600, while the sum is 61.

The spelling of 9991354029253 in words is "nine trillion, nine hundred ninety-one billion, three hundred fifty-four million, twenty-nine thousand, two hundred fifty-three".