Search a number
-
+
999987000000 = 263562571297
BaseRepresentation
bin11101000110100111101…
…11101011001011000000
310112121010210221221211120
432203103313223023000
5112340433133000000
62043215423512240
7132150416153112
oct16432367531300
93477123857746
10999987000000
1135610165689a
12141979758680
13733b5696631
14365848213b2
151b02a5496a0
hexe8d3deb2c0

999987000000 has 392 divisors, whose sum is σ = 3322634657232. Its totient is φ = 265420800000.

The previous prime is 999986999983. The next prime is 999987000007. The reversal of 999987000000 is 789999.

It is a nialpdrome in base 10.

It is a junction number, because it is equal to n+sod(n) for n = 999986999898 and 999986999907.

It is not an unprimeable number, because it can be changed into a prime (999987000007) by changing a digit.

It is a polite number, since it can be written in 55 ways as a sum of consecutive naturals, for example, 770999352 + ... + 771000648.

Almost surely, 2999987000000 is an apocalyptic number.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 999987000000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (1661317328616).

999987000000 is an abundant number, since it is smaller than the sum of its proper divisors (2322647657232).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

999987000000 is an equidigital number, since it uses as much as digits as its factorization.

999987000000 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1599 (or 1564 counting only the distinct ones).

The product of its (nonzero) digits is 367416, while the sum is 51.

Adding to 999987000000 its reverse (789999), we get a palindrome (999987789999).

The spelling of 999987000000 in words is "nine hundred ninety-nine billion, nine hundred eighty-seven million", and thus it is an aban number.