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10000011010147 is a prime number
BaseRepresentation
bin1001000110000100111100…
…0110101010000001100011
31022101222202221221121220121
42101201033012222001203
52302320010304311042
633133535221021111
72051322411051664
oct221411706520143
938358687847817
1010000011010147
113205a87574114
12115609b554797
13576cc6511ac2
1426800879736b
151251cadba367
hex9184f1aa063

10000011010147 has 2 divisors, whose sum is σ = 10000011010148. Its totient is φ = 10000011010146.

The previous prime is 10000011010109. The next prime is 10000011010151. The reversal of 10000011010147 is 74101011000001.

It is a happy number.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 10000011010147 - 227 = 9999876792419 is a prime.

It is a super-3 number, since 3×100000110101473 (a number of 40 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a self number, because there is not a number n which added to its sum of digits gives 10000011010147.

It is not a weakly prime, because it can be changed into another prime (10000011010547) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5000005505073 + 5000005505074.

It is an arithmetic number, because the mean of its divisors is an integer number (5000005505074).

Almost surely, 210000011010147 is an apocalyptic number.

10000011010147 is a deficient number, since it is larger than the sum of its proper divisors (1).

10000011010147 is an equidigital number, since it uses as much as digits as its factorization.

10000011010147 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 28, while the sum is 16.

Adding to 10000011010147 its reverse (74101011000001), we get a palindrome (84101022010148).

The spelling of 10000011010147 in words is "ten trillion, eleven million, ten thousand, one hundred forty-seven".