100000113001333 has 2 divisors, whose sum is σ = 100000113001334. Its totient is φ = 100000113001332.

The previous prime is 100000113001207. The next prime is 100000113001361. The reversal of 100000113001333 is 333100311000001.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 77269321348209 + 22730791653124 = 8790297^2 + 4767682^2 .

It is an emirp because it is prime and its reverse (333100311000001) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 100000113001333 - 2³³ = 99991523066741 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (100000113031333) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50000056500666 + 50000056500667.

It is an arithmetic number, because the mean of its divisors is an integer number (50000056500667).

Almost surely, 2^{100000113001333} is an apocalyptic number.

It is an amenable number.

100000113001333 is a deficient number, since it is larger than the sum of its proper divisors (1).

100000113001333 is an equidigital number, since it uses as much as digits as its factorization.

100000113001333 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 81, while the sum is 16.

Adding to 100000113001333 its reverse (333100311000001), we get a palindrome (433100424001334).

The spelling of 100000113001333 in words is "one hundred trillion, one hundred thirteen million, one thousand, three hundred thirty-three".