Base | Representation |
---|---|
bin | 101110100100010000… |
… | …1100010101011000011 |
3 | 100120010020112011011121 |
4 | 1131020201202223003 |
5 | 3114300224001011 |
6 | 113535000253111 |
7 | 10140055322224 |
oct | 1351041425303 |
9 | 316106464147 |
10 | 100001000131 |
11 | 39456a5955a |
12 | 1746a171197 |
13 | 9578a9ca36 |
14 | 4ba924124b |
15 | 2904385e71 |
hex | 1748862ac3 |
100001000131 has 2 divisors, whose sum is σ = 100001000132. Its totient is φ = 100001000130.
The previous prime is 100001000117. The next prime is 100001000137. The reversal of 100001000131 is 131000100001.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 100001000131 - 233 = 91411065539 is a prime.
It is a super-2 number, since 2×1000010001312 (a number of 23 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (100001000137) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50000500065 + 50000500066.
It is an arithmetic number, because the mean of its divisors is an integer number (50000500066).
Almost surely, 2100001000131 is an apocalyptic number.
100001000131 is a deficient number, since it is larger than the sum of its proper divisors (1).
100001000131 is an equidigital number, since it uses as much as digits as its factorization.
100001000131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3, while the sum is 7.
Adding to 100001000131 its reverse (131000100001), we get a palindrome (231001100132).
The spelling of 100001000131 in words is "one hundred billion, one million, one hundred thirty-one", and thus it is an aban number.
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