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10000119901 = 22344843587
BaseRepresentation
bin10010101000000110…
…11011100001011101
3221210220222201121011
421110003123201131
5130440012314101
64332145135221
7502545421342
oct112403334135
927726881534
1010000119901
114271897102
121b3102a511
13c34a2cc15
146ac1947c9
153d7dd3751
hex2540db85d

10000119901 has 4 divisors (see below), whose sum is σ = 10044963712. Its totient is φ = 9955276092.

The previous prime is 10000119893. The next prime is 10000119917. The reversal of 10000119901 is 10991100001.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 10991100001 = 71570157143.

It is a cyclic number.

It is not a de Polignac number, because 10000119901 - 23 = 10000119893 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (10000119931) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 22421571 + ... + 22422016.

It is an arithmetic number, because the mean of its divisors is an integer number (2511240928).

Almost surely, 210000119901 is an apocalyptic number.

It is an amenable number.

10000119901 is a deficient number, since it is larger than the sum of its proper divisors (44843811).

10000119901 is an equidigital number, since it uses as much as digits as its factorization.

10000119901 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 44843810.

The product of its (nonzero) digits is 81, while the sum is 22.

Adding to 10000119901 its reverse (10991100001), we get a palindrome (20991219902).

The spelling of 10000119901 in words is "ten billion, one hundred nineteen thousand, nine hundred one".

Divisors: 1 223 44843587 10000119901