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100001303133 = 333333767711
BaseRepresentation
bin101110100100010001…
…0101100101001011101
3100120010021002112210220
41131020202230221131
53114300313200013
6113535010551553
710140061023504
oct1351042545135
9316107075726
10100001303133
1139457146176
121746a2985b9
139578b77924
144ba92bd83b
1529043e5b23
hex17488aca5d

100001303133 has 4 divisors (see below), whose sum is σ = 133335070848. Its totient is φ = 66667535420.

The previous prime is 100001303123. The next prime is 100001303137. The reversal of 100001303133 is 331303100001.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 331303100001 = 3110434366667.

It is a cyclic number.

It is not a de Polignac number, because 100001303133 - 26 = 100001303069 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (100001303137) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 16666883853 + ... + 16666883858.

It is an arithmetic number, because the mean of its divisors is an integer number (33333767712).

Almost surely, 2100001303133 is an apocalyptic number.

It is an amenable number.

100001303133 is a deficient number, since it is larger than the sum of its proper divisors (33333767715).

100001303133 is an equidigital number, since it uses as much as digits as its factorization.

100001303133 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 33333767714.

The product of its (nonzero) digits is 81, while the sum is 15.

Adding to 100001303133 its reverse (331303100001), we get a palindrome (431304403134).

The spelling of 100001303133 in words is "one hundred billion, one million, three hundred three thousand, one hundred thirty-three".

Divisors: 1 3 33333767711 100001303133