Base | Representation |
---|---|
bin | 101110100100010110… |
… | …1000001110100101111 |
3 | 100120010110012010201210 |
4 | 1131020231001310233 |
5 | 3114302011330221 |
6 | 113535145005503 |
7 | 10140123033201 |
oct | 1351055016457 |
9 | 316113163653 |
10 | 100004011311 |
11 | 39458725936 |
12 | 1746b183893 |
13 | 95795b54b9 |
14 | 4ba97c6771 |
15 | 290477d276 |
hex | 1748b41d2f |
100004011311 has 4 divisors (see below), whose sum is σ = 133338681752. Its totient is φ = 66669340872.
The previous prime is 100004011309. The next prime is 100004011397. The reversal of 100004011311 is 113110400001.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 113110400001 = 3 ⋅37703466667.
It is not a de Polignac number, because 100004011311 - 21 = 100004011309 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (100004018311) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 16667335216 + ... + 16667335221.
It is an arithmetic number, because the mean of its divisors is an integer number (33334670438).
Almost surely, 2100004011311 is an apocalyptic number.
100004011311 is a deficient number, since it is larger than the sum of its proper divisors (33334670441).
100004011311 is an equidigital number, since it uses as much as digits as its factorization.
100004011311 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 33334670440.
The product of its (nonzero) digits is 12, while the sum is 12.
Adding to 100004011311 its reverse (113110400001), we get a palindrome (213114411312).
The spelling of 100004011311 in words is "one hundred billion, four million, eleven thousand, three hundred eleven".
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