Search a number
-
+
100004011311 = 333334670437
BaseRepresentation
bin101110100100010110…
…1000001110100101111
3100120010110012010201210
41131020231001310233
53114302011330221
6113535145005503
710140123033201
oct1351055016457
9316113163653
10100004011311
1139458725936
121746b183893
1395795b54b9
144ba97c6771
15290477d276
hex1748b41d2f

100004011311 has 4 divisors (see below), whose sum is σ = 133338681752. Its totient is φ = 66669340872.

The previous prime is 100004011309. The next prime is 100004011397. The reversal of 100004011311 is 113110400001.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 113110400001 = 337703466667.

It is not a de Polignac number, because 100004011311 - 21 = 100004011309 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (100004018311) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 16667335216 + ... + 16667335221.

It is an arithmetic number, because the mean of its divisors is an integer number (33334670438).

Almost surely, 2100004011311 is an apocalyptic number.

100004011311 is a deficient number, since it is larger than the sum of its proper divisors (33334670441).

100004011311 is an equidigital number, since it uses as much as digits as its factorization.

100004011311 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 33334670440.

The product of its (nonzero) digits is 12, while the sum is 12.

Adding to 100004011311 its reverse (113110400001), we get a palindrome (213114411312).

The spelling of 100004011311 in words is "one hundred billion, four million, eleven thousand, three hundred eleven".

Divisors: 1 3 33334670437 100004011311