Base | Representation |
---|---|
bin | 10110101111010101100101… |
… | …001011111000011100110111 |
3 | 111010002212022121222011002121 |
4 | 112233111211023320130313 |
5 | 101102031000320212413 |
6 | 552411544223220411 |
7 | 30031325210120464 |
oct | 2657254513703467 |
9 | 433085277864077 |
10 | 100010011100983 |
11 | 2995900a013555 |
12 | b27273a447707 |
13 | 43a5b9921c139 |
14 | 1a9a72062466b |
15 | b86753621b8d |
hex | 5af5652f8737 |
100010011100983 has 2 divisors, whose sum is σ = 100010011100984. Its totient is φ = 100010011100982.
The previous prime is 100010011100977. The next prime is 100010011101001. The reversal of 100010011100983 is 389001110010001.
It is a weak prime.
It is an emirp because it is prime and its reverse (389001110010001) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 100010011100983 - 221 = 100010009003831 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (100010011100683) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50005005550491 + 50005005550492.
It is an arithmetic number, because the mean of its divisors is an integer number (50005005550492).
Almost surely, 2100010011100983 is an apocalyptic number.
100010011100983 is a deficient number, since it is larger than the sum of its proper divisors (1).
100010011100983 is an equidigital number, since it uses as much as digits as its factorization.
100010011100983 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 216, while the sum is 25.
Adding to 100010011100983 its reverse (389001110010001), we get a palindrome (489011121110984).
The spelling of 100010011100983 in words is "one hundred trillion, ten billion, eleven million, one hundred thousand, nine hundred eighty-three".
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