100010100000113 has 2 divisors, whose sum is σ = 100010100000114. Its totient is φ = 100010100000112.

The previous prime is 100010100000071. The next prime is 100010100000133. The reversal of 100010100000113 is 311000001010001.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 87816259487089 + 12193840513024 = 9371033^2 + 3491968^2 .

It is a cyclic number.

It is not a de Polignac number, because 100010100000113 - 2¹² = 100010099996017 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 100010100000113.

It is not a weakly prime, because it can be changed into another prime (100010100000133) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50005050000056 + 50005050000057.

It is an arithmetic number, because the mean of its divisors is an integer number (50005050000057).

Almost surely, 2^{100010100000113} is an apocalyptic number.

It is an amenable number.

100010100000113 is a deficient number, since it is larger than the sum of its proper divisors (1).

100010100000113 is an equidigital number, since it uses as much as digits as its factorization.

100010100000113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 3, while the sum is 8.

Adding to 100010100000113 its reverse (311000001010001), we get a palindrome (411010101010114).

The spelling of 100010100000113 in words is "one hundred trillion, ten billion, one hundred million, one hundred thirteen", and thus it is an aban number.