Base | Representation |
---|---|
bin | 11101000110110101011… |
… | …10011010000010100011 |
3 | 10112121102211101010022211 |
4 | 32203122232122002203 |
5 | 112341202103323133 |
6 | 2043235052542551 |
7 | 132153313555222 |
oct | 16433256320243 |
9 | 3477384333284 |
10 | 1000102011043 |
11 | 356160570343 |
12 | 1419b0181a57 |
13 | 734034647c5 |
14 | 36595bdccb9 |
15 | 1b0356b6bcd |
hex | e8dab9a0a3 |
1000102011043 has 2 divisors, whose sum is σ = 1000102011044. Its totient is φ = 1000102011042.
The previous prime is 1000102011017. The next prime is 1000102011091. The reversal of 1000102011043 is 3401102010001.
1000102011043 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1000102011043 - 25 = 1000102011011 is a prime.
It is not a weakly prime, because it can be changed into another prime (1000102011443) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 500051005521 + 500051005522.
It is an arithmetic number, because the mean of its divisors is an integer number (500051005522).
Almost surely, 21000102011043 is an apocalyptic number.
1000102011043 is a deficient number, since it is larger than the sum of its proper divisors (1).
1000102011043 is an equidigital number, since it uses as much as digits as its factorization.
1000102011043 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 24, while the sum is 13.
Adding to 1000102011043 its reverse (3401102010001), we get a palindrome (4401204021044).
The spelling of 1000102011043 in words is "one trillion, one hundred two million, eleven thousand, forty-three".
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