Base | Representation |
---|---|
bin | 10110101111010101110000… |
… | …100100000110101011010011 |
3 | 111010002212210221011211102122 |
4 | 112233111300210012223103 |
5 | 101102031343203000313 |
6 | 552412015203004455 |
7 | 30031333015541564 |
oct | 2657256044065323 |
9 | 433085727154378 |
10 | 100010202000083 |
11 | 299590a784a901 |
12 | b27279236972b |
13 | 43a5bc993ab9b |
14 | 1a9a73bb1816b |
15 | b8676527e708 |
hex | 5af570906ad3 |
100010202000083 has 2 divisors, whose sum is σ = 100010202000084. Its totient is φ = 100010202000082.
The previous prime is 100010201999999. The next prime is 100010202000221. The reversal of 100010202000083 is 380000202010001.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 100010202000083 - 218 = 100010201737939 is a prime.
It is a Sophie Germain prime.
It is not a weakly prime, because it can be changed into another prime (100010202003083) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50005101000041 + 50005101000042.
It is an arithmetic number, because the mean of its divisors is an integer number (50005101000042).
Almost surely, 2100010202000083 is an apocalyptic number.
100010202000083 is a deficient number, since it is larger than the sum of its proper divisors (1).
100010202000083 is an equidigital number, since it uses as much as digits as its factorization.
100010202000083 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 96, while the sum is 17.
Adding to 100010202000083 its reverse (380000202010001), we get a palindrome (480010404010084).
The spelling of 100010202000083 in words is "one hundred trillion, ten billion, two hundred two million, eighty-three", and thus it is an aban number.
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