10001040010433 has 2 divisors, whose sum is σ = 10001040010434. Its totient is φ = 10001040010432.

The previous prime is 10001040010343. The next prime is 10001040010469. The reversal of 10001040010433 is 33401004010001.

Together with previous prime (10001040010343) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 9934492521409 + 66547489024 = 3151903^2 + 257968^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-10001040010433 is a prime.

It is not a weakly prime, because it can be changed into another prime (10001040010033) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5000520005216 + 5000520005217.

It is an arithmetic number, because the mean of its divisors is an integer number (5000520005217).

Almost surely, 2^{10001040010433} is an apocalyptic number.

It is an amenable number.

10001040010433 is a deficient number, since it is larger than the sum of its proper divisors (1).

10001040010433 is an equidigital number, since it uses as much as digits as its factorization.

10001040010433 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 144, while the sum is 17.

Adding to 10001040010433 its reverse (33401004010001), we get a palindrome (43402044020434).

The spelling of 10001040010433 in words is "ten trillion, one billion, forty million, ten thousand, four hundred thirty-three".