10001104104113 has 8 divisors (see below), whose sum is σ = 10575518424576. Its totient is φ = 9442427162400.

The previous prime is 10001104104041. The next prime is 10001104104133. The reversal of 10001104104113 is 31140140110001.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 10001104104113 - 2²² = 10001099909809 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 10001104104091 and 10001104104100.

It is not an unprimeable number, because it can be changed into a prime (10001104104133) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 3934343381 + ... + 3934345922.

It is an arithmetic number, because the mean of its divisors is an integer number (1321939803072).

Almost surely, 2^{10001104104113} is an apocalyptic number.

It is an amenable number.

10001104104113 is a deficient number, since it is larger than the sum of its proper divisors (574414320463).

10001104104113 is an equidigital number, since it uses as much as digits as its factorization.

10001104104113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 7868689375.

The product of its (nonzero) digits is 48, while the sum is 17.

Adding to 10001104104113 its reverse (31140140110001), we get a palindrome (41141244214114).

The spelling of 10001104104113 in words is "ten trillion, one billion, one hundred four million, one hundred four thousand, one hundred thirteen".