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100011100000583 is a prime number
BaseRepresentation
bin10110101111010110100110…
…000101101101000101000111
3111010002222010111220222112102
4112233112212011231011013
5101102040213100004313
6552412244242142315
730031364201452052
oct2657264605550507
9433088114828472
10100011100000583
1129959518736982
12b2729a305199b
1343a60109b4425
141a9a7c50b3a99
15b867b9013a58
hex5af5a616d147

100011100000583 has 2 divisors, whose sum is σ = 100011100000584. Its totient is φ = 100011100000582.

The previous prime is 100011100000577. The next prime is 100011100000601. The reversal of 100011100000583 is 385000001110001.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 100011100000583 - 214 = 100011099984199 is a prime.

It is a super-2 number, since 2×1000111000005832 (a number of 29 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (100011100000183) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50005550000291 + 50005550000292.

It is an arithmetic number, because the mean of its divisors is an integer number (50005550000292).

Almost surely, 2100011100000583 is an apocalyptic number.

100011100000583 is a deficient number, since it is larger than the sum of its proper divisors (1).

100011100000583 is an equidigital number, since it uses as much as digits as its factorization.

100011100000583 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 120, while the sum is 20.

Adding to 100011100000583 its reverse (385000001110001), we get a palindrome (485011101110584).

The spelling of 100011100000583 in words is "one hundred trillion, eleven billion, one hundred million, five hundred eighty-three", and thus it is an aban number.