10001111099983 has 2 divisors, whose sum is σ = 10001111099984. Its totient is φ = 10001111099982.

The previous prime is 10001111099953. The next prime is 10001111100011. The reversal of 10001111099983 is 38999011110001.

It is a strong prime.

It is an emirp because it is prime and its reverse (38999011110001) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 10001111099983 - 2³³ = 9992521165391 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (10001111099933) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5000555549991 + 5000555549992.

It is an arithmetic number, because the mean of its divisors is an integer number (5000555549992).

Almost surely, 2^{10001111099983} is an apocalyptic number.

10001111099983 is a deficient number, since it is larger than the sum of its proper divisors (1).

10001111099983 is an equidigital number, since it uses as much as digits as its factorization.

10001111099983 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 17496, while the sum is 43.

It can be divided in two parts, 1000111109998 and 3, that added together give a palindrome (1000111110001).

The spelling of 10001111099983 in words is "ten trillion, one billion, one hundred eleven million, ninety-nine thousand, nine hundred eighty-three".