Base | Representation |
---|---|
bin | 11101000110110110101… |
… | …01000011001110010111 |
3 | 10112121110112102210022002 |
4 | 32203123111003032113 |
5 | 112341212202004312 |
6 | 2043240054025515 |
7 | 132153465636224 |
oct | 16433325031627 |
9 | 3477415383262 |
10 | 1000112141207 |
11 | 35616625a283 |
12 | 1419b364829b |
13 | 734055a069a |
14 | 365972b894b |
15 | 1b0365184c2 |
hex | e8db543397 |
1000112141207 has 2 divisors, whose sum is σ = 1000112141208. Its totient is φ = 1000112141206.
The previous prime is 1000112141191. The next prime is 1000112141221. The reversal of 1000112141207 is 7021412110001.
It is a strong prime.
It is an emirp because it is prime and its reverse (7021412110001) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1000112141207 - 24 = 1000112141191 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1000112141257) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 500056070603 + 500056070604.
It is an arithmetic number, because the mean of its divisors is an integer number (500056070604).
Almost surely, 21000112141207 is an apocalyptic number.
1000112141207 is a deficient number, since it is larger than the sum of its proper divisors (1).
1000112141207 is an equidigital number, since it uses as much as digits as its factorization.
1000112141207 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 112, while the sum is 20.
Adding to 1000112141207 its reverse (7021412110001), we get a palindrome (8021524251208).
The spelling of 1000112141207 in words is "one trillion, one hundred twelve million, one hundred forty-one thousand, two hundred seven".
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