100011230113 has 4 divisors (see below), whose sum is σ = 100012960000. Its totient is φ = 100009500228.

The previous prime is 100011230087. The next prime is 100011230117. The reversal of 100011230113 is 311032110001.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 100011230113 - 2³³ = 91421295521 is a prime.

It is a super-2 number, since 2×100011230113² (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 100011230093 and 100011230102.

It is not an unprimeable number, because it can be changed into a prime (100011230117) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 775113 + ... + 894886.

It is an arithmetic number, because the mean of its divisors is an integer number (25003240000).

Almost surely, 2^100011230113 is an apocalyptic number.

It is an amenable number.

100011230113 is a deficient number, since it is larger than the sum of its proper divisors (1729887).

100011230113 is an equidigital number, since it uses as much as digits as its factorization.

100011230113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1729886.

The product of its (nonzero) digits is 18, while the sum is 13.

Adding to 100011230113 its reverse (311032110001), we get a palindrome (411043340114).

It can be divided in two parts, 1000112 and 30113, that added together give a square (1030225 = 1015²).

The spelling of 100011230113 in words is "one hundred billion, eleven million, two hundred thirty thousand, one hundred thirteen".