Base | Representation |
---|---|
bin | 1001000110001001000111… |
… | …1110110111111100010101 |
3 | 1022102002200011020211021121 |
4 | 2101202101332313330111 |
5 | 2302324310024342402 |
6 | 33134242422043541 |
7 | 2051362254143122 |
oct | 221422176677425 |
9 | 38362604224247 |
10 | 10001133043477 |
11 | 3206502968394 |
12 | 11563532795b1 |
13 | 577144b08554 |
14 | 2680b37cd749 |
15 | 125244654837 |
hex | 91891fb7f15 |
10001133043477 has 2 divisors, whose sum is σ = 10001133043478. Its totient is φ = 10001133043476.
The previous prime is 10001133043339. The next prime is 10001133043507. The reversal of 10001133043477 is 77434033110001.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 6574639579236 + 3426493464241 = 2564106^2 + 1851079^2 .
It is a cyclic number.
It is not a de Polignac number, because 10001133043477 - 227 = 10000998825749 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (10001133043177) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5000566521738 + 5000566521739.
It is an arithmetic number, because the mean of its divisors is an integer number (5000566521739).
Almost surely, 210001133043477 is an apocalyptic number.
It is an amenable number.
10001133043477 is a deficient number, since it is larger than the sum of its proper divisors (1).
10001133043477 is an equidigital number, since it uses as much as digits as its factorization.
10001133043477 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 21168, while the sum is 34.
Adding to 10001133043477 its reverse (77434033110001), we get a palindrome (87435166153478).
The spelling of 10001133043477 in words is "ten trillion, one billion, one hundred thirty-three million, forty-three thousand, four hundred seventy-seven".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.073 sec. • engine limits •