Base | Representation |
---|---|
bin | 10010101000001110… |
… | …10111000001000001 |
3 | 221210222221001122121 |
4 | 21110013113001001 |
5 | 130440243300032 |
6 | 4332223204241 |
7 | 502560241525 |
oct | 112407270101 |
9 | 27728831577 |
10 | 10001150017 |
11 | 4272430041 |
12 | 1b31446681 |
13 | c35000a61 |
14 | 6ac381d85 |
15 | 3d8038a97 |
hex | 2541d7041 |
10001150017 has 4 divisors (see below), whose sum is σ = 10002134016. Its totient is φ = 10000166020.
The previous prime is 10001150009. The next prime is 10001150059. The reversal of 10001150017 is 71005110001.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 10001150017 - 23 = 10001150009 is a prime.
It is a super-3 number, since 3×100011500173 (a number of 31 digits) contains 333 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (10001150077) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (13) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 476593 + ... + 497134.
It is an arithmetic number, because the mean of its divisors is an integer number (2500533504).
Almost surely, 210001150017 is an apocalyptic number.
It is an amenable number.
10001150017 is a deficient number, since it is larger than the sum of its proper divisors (983999).
10001150017 is an equidigital number, since it uses as much as digits as its factorization.
10001150017 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 983998.
The product of its (nonzero) digits is 35, while the sum is 16.
Adding to 10001150017 its reverse (71005110001), we get a palindrome (81006260018).
The spelling of 10001150017 in words is "ten billion, one million, one hundred fifty thousand, seventeen".
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