Base | Representation |
---|---|
bin | 10110101111010111101000… |
… | …010100100110010101000011 |
3 | 111010010001222221211211102021 |
4 | 112233113220110212111003 |
5 | 101102100002031420342 |
6 | 552412550415102311 |
7 | 30031433553505324 |
oct | 2657275024462503 |
9 | 433101887754367 |
10 | 100012211201347 |
11 | 29959a38a01515 |
12 | b273053211997 |
13 | 43a6159c87383 |
14 | 1a9a88c8ca44b |
15 | b8683185d567 |
hex | 5af5e8526543 |
100012211201347 has 2 divisors, whose sum is σ = 100012211201348. Its totient is φ = 100012211201346.
The previous prime is 100012211201321. The next prime is 100012211201351. The reversal of 100012211201347 is 743102112210001.
It is a happy number.
It is a strong prime.
It is an emirp because it is prime and its reverse (743102112210001) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 100012211201347 - 27 = 100012211201219 is a prime.
It is a super-2 number, since 2×1000122112013472 (a number of 29 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (100012211271347) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50006105600673 + 50006105600674.
It is an arithmetic number, because the mean of its divisors is an integer number (50006105600674).
Almost surely, 2100012211201347 is an apocalyptic number.
100012211201347 is a deficient number, since it is larger than the sum of its proper divisors (1).
100012211201347 is an equidigital number, since it uses as much as digits as its factorization.
100012211201347 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 672, while the sum is 25.
Adding to 100012211201347 its reverse (743102112210001), we get a palindrome (843114323411348).
The spelling of 100012211201347 in words is "one hundred trillion, twelve billion, two hundred eleven million, two hundred one thousand, three hundred forty-seven".
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