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100012224433 = 1153819168937
BaseRepresentation
bin101110100100100110…
…0010110111110110001
3100120011000122102000111
41131021030112332301
53114311112140213
6113540041021321
710140252611152
oct1351114267661
9316130572014
10100012224433
1139462325540
1217471a84841
13957b1cc934
144baa923929
152905351a3d
hex1749316fb1

100012224433 has 8 divisors (see below), whose sum is σ = 109106917920. Its totient is φ = 90917976480.

The previous prime is 100012224359. The next prime is 100012224457. The reversal of 100012224433 is 334422210001.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-100012224433 is a prime.

It is a super-3 number, since 3×1000122244333 (a number of 34 digits) contains 333 as substring.

It is not an unprimeable number, because it can be changed into a prime (100012224463) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 507541 + ... + 676477.

It is an arithmetic number, because the mean of its divisors is an integer number (13638364740).

Almost surely, 2100012224433 is an apocalyptic number.

It is an amenable number.

100012224433 is a deficient number, since it is larger than the sum of its proper divisors (9094693487).

100012224433 is a wasteful number, since it uses less digits than its factorization.

100012224433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 222767.

The product of its (nonzero) digits is 1152, while the sum is 22.

Adding to 100012224433 its reverse (334422210001), we get a palindrome (434434434434).

The spelling of 100012224433 in words is "one hundred billion, twelve million, two hundred twenty-four thousand, four hundred thirty-three".

Divisors: 1 11 53819 168937 592009 1858307 9092020403 100012224433