Base | Representation |
---|---|
bin | 101110100100100110… |
… | …0101100100110100101 |
3 | 100120011000210220111122 |
4 | 1131021030230212211 |
5 | 3114311123003442 |
6 | 113540042543325 |
7 | 10140253430312 |
oct | 1351114544645 |
9 | 316130726448 |
10 | 100012312997 |
11 | 39462386033 |
12 | 17471b07b45 |
13 | 957b23103c |
14 | 4baa947d09 |
15 | 290536cdd2 |
hex | 174932c9a5 |
100012312997 has 2 divisors, whose sum is σ = 100012312998. Its totient is φ = 100012312996.
The previous prime is 100012312979. The next prime is 100012313039. The reversal of 100012312997 is 799213210001.
Together with previous prime (100012312979) it forms an Ormiston pair, because they use the same digits, order apart.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 68560709281 + 31451603716 = 261841^2 + 177346^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-100012312997 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (100012312937) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50006156498 + 50006156499.
It is an arithmetic number, because the mean of its divisors is an integer number (50006156499).
Almost surely, 2100012312997 is an apocalyptic number.
It is an amenable number.
100012312997 is a deficient number, since it is larger than the sum of its proper divisors (1).
100012312997 is an equidigital number, since it uses as much as digits as its factorization.
100012312997 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 6804, while the sum is 35.
Adding to 100012312997 its reverse (799213210001), we get a palindrome (899225522998).
The spelling of 100012312997 in words is "one hundred billion, twelve million, three hundred twelve thousand, nine hundred ninety-seven".
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