10001300113 has 4 divisors (see below), whose sum is σ = 11430057280. Its totient is φ = 8572542948.

The previous prime is 10001300083. The next prime is 10001300119. The reversal of 10001300113 is 31100310001.

10001300113 is digitally balanced in base 2 and base 3, because in such bases it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 10001300113 - 2⁹ = 10001299601 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 10001300113.

It is not an unprimeable number, because it can be changed into a prime (10001300119) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 714378573 + ... + 714378586.

It is an arithmetic number, because the mean of its divisors is an integer number (2857514320).

Almost surely, 2^10001300113 is an apocalyptic number.

It is an amenable number.

10001300113 is a deficient number, since it is larger than the sum of its proper divisors (1428757167).

10001300113 is an equidigital number, since it uses as much as digits as its factorization.

10001300113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1428757166.

The product of its (nonzero) digits is 9, while the sum is 10.

Adding to 10001300113 its reverse (31100310001), we get a palindrome (41101610114).

The spelling of 10001300113 in words is "ten billion, one million, three hundred thousand, one hundred thirteen".