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1000130012103 = 3333376670701
BaseRepresentation
bin11101000110111000110…
…01001110001111000111
310112121111210001201120010
432203130121032033013
5112341231240341403
62043241533041303
7132154103560035
oct16433431161707
93477453051503
101000130012103
11356175355a12
121419b9626233
13734091b9991
143659980b555
151b037d98603
hexe8dc64e3c7

1000130012103 has 4 divisors (see below), whose sum is σ = 1333506682808. Its totient is φ = 666753341400.

The previous prime is 1000130012093. The next prime is 1000130012107. The reversal of 1000130012103 is 3012100310001.

It is a semiprime because it is the product of two primes.

It is not a de Polignac number, because 1000130012103 - 26 = 1000130012039 is a prime.

It is a super-2 number, since 2×10001300121032 (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1000130012107) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 166688335348 + ... + 166688335353.

It is an arithmetic number, because the mean of its divisors is an integer number (333376670702).

Almost surely, 21000130012103 is an apocalyptic number.

1000130012103 is a deficient number, since it is larger than the sum of its proper divisors (333376670705).

1000130012103 is an equidigital number, since it uses as much as digits as its factorization.

1000130012103 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 333376670704.

The product of its (nonzero) digits is 18, while the sum is 12.

Adding to 1000130012103 its reverse (3012100310001), we get a palindrome (4012230322104).

The spelling of 1000130012103 in words is "one trillion, one hundred thirty million, twelve thousand, one hundred three".

Divisors: 1 3 333376670701 1000130012103