Base | Representation |
---|---|
bin | 11101000110111000110… |
… | …01101011110010001011 |
3 | 10112121111210021212120122 |
4 | 32203130121223302023 |
5 | 112341231303230011 |
6 | 2043241535413455 |
7 | 132154104602633 |
oct | 16433431536213 |
9 | 3477453255518 |
10 | 1000130133131 |
11 | 356175428938 |
12 | 1419b968428b |
13 | 7340922caac |
14 | 3659983d6c3 |
15 | 1b037dbe3db |
hex | e8dc66bc8b |
1000130133131 has 8 divisors (see below), whose sum is σ = 1001928644640. Its totient is φ = 998332985728.
The previous prime is 1000130133103. The next prime is 1000130133161. The reversal of 1000130133131 is 1313310310001.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 1000130133131 - 214 = 1000130116747 is a prime.
It is a super-2 number, since 2×10001301331312 (a number of 25 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (1000130133161) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1132355 + ... + 1811763.
It is an arithmetic number, because the mean of its divisors is an integer number (125241080580).
Almost surely, 21000130133131 is an apocalyptic number.
1000130133131 is a deficient number, since it is larger than the sum of its proper divisors (1798511509).
1000130133131 is an equidigital number, since it uses as much as digits as its factorization.
1000130133131 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 682053.
The product of its (nonzero) digits is 81, while the sum is 17.
Adding to 1000130133131 its reverse (1313310310001), we get a palindrome (2313440443132).
The spelling of 1000130133131 in words is "one trillion, one hundred thirty million, one hundred thirty-three thousand, one hundred thirty-one".
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